For a mathrmMg mid mathrmMg^2+ (aq) parallel mathrmAg^+(mathrmaq) mid mathrmAg the correct Nernst Equation is :

Solution & Explanation

### Related Formula E_textcell = E_textcell^circ - fracRTnF ln Q ### Core Logic Let us explicitly formulate the complete chemical oxidation-reduction equations : Anode oxidation: mathrmMg_(s) rightarrow mathrmMg^2+_(aq) + 2e^- Cathode reduction: 2mathrmAg^+_(aq) + 2e^- rightarrow 2mathrmAg_(s) Net total equation : mathrmMg_(s) + 2mathrmAg^+_(aq) rightleftharpoons mathrmMg^2+_(aq) + 2mathrmAg_(s) Total transferred moles of electrons n = 2 . Reaction quotient : Q = frac[mathrmMg^2+][mathrmAg^+]^2 Substituting into Nernst form : E_textcell = E_textcell^circ - fracRT2F lnleft( frac[mathrmMg^2+][mathrmAg^+]^2 right) Inverting the inside quotient changes the sign of the logarithm term from negative to positive: E_textcell = E_textcell^circ + fracRT2F lnleft( frac[mathrmAg^+]^2[mathrmMg^2+] right) ### Pattern Recognition A standard negative logarithmic quotient can always toggle into an addition configuration by inverting the products/reactants variables concentration ratio.

More Electrochemistry Previous-Year Questions — Page 6

Q65 jee_main_2024_31_jan_morning Batteries
The metals that are employed in the battery industries are A. Fe B. Mn C. Ni D. Cr E. Cd Choose the correct answer from the options given below:
  • A. textB, C and E only
  • B. textA, B, C, D and E
  • C. textA, B, C and D only
  • D. textB, D and E only

Solution

### Core Logic Mn, Ni, and Cd metals are predominantly used in battery industries. - Mn is used in dry cells (Leclanche cell). - Ni and Cd are used in Nickel-Cadmium (Ni-Cd) rechargeable batteries. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Electrochemistry
Q67 jee_main_2024_31_jan_morning Electrolytic Conductance
Identify the factor from the following that does not affect electrolytic conductance of a solution.
  • A. textThe nature of the electrolyte added.
  • B. textThe nature of the electrode used.
  • C. textConcentration of the electrolyte.
  • D. textThe nature of solvent used.

Solution

### Core Logic Conductivity of an electrolytic cell is affected by the concentration of the electrolyte, the nature of the electrolyte, and the nature of the solvent. It does not depend on the nature of the electrode used. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Electrochemistry
Q90 jee_main_2024_31_jan_morning Faraday's Laws of Electrolysis
One Faraday of electricity liberates x times 10^-1 gram atom of copper from copper sulphate, x is
Numerical Answer. Answer: 5 to 5

Solution

### Core Logic The reduction reaction for copper is: Cu^2+ + 2e^- rightarrow Cu This shows that 2 moles of electrons (2 Faraday) are required to deposit 1 mole (or 1 gram atom) of Cu. Therefore, 1 Faraday of electricity will deposit: frac12 = 0.5 text moles of Cu ### Step 1: Finding x 0.5 text mole = 0.5 text gram atom = 5 times 10^-1 text gram atom Hence, x = 5. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Electrochemistry
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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)