Let f: mathbbR to mathbbR be a function defined by f(x) = (2 + 3a)x^2 + left( fraca + 2a - 1 right)x + b, a neq 1. If f(x + y) = f(x) + f(y) + 1 - frac27xy, then the value of 28sum_i = 1^5|f(i)| is: (1) 715 (2) 735 (3) 545 (4) 675

Solution & Explanation

### Related Formula Given functional property equation: f(x + y) = f(x) + f(y) + 1 - frac27xy ### Core Logic Substitute x = y = 0 into the property equation: f(0) = 2f(0) + 1 implies f(0) = -1. Since f(0) = b, we instantly find b = -1. ### Step 1: Extracting Parameter Values Substitute y = -x into the property equation: f(0) = f(x) + f(-x) + 1 + frac27x^2 -1 = 2(3a + 2)x^2 + 2b + 1 + frac27x^2 Matching coefficients for x^2 gives: 6a + 4 + frac27 = 0 implies a = -frac57 Therefore, the absolute functional identity is: f(x) = -frac17x^2 - frac34x - 1 ### Step 2: Computing the Target Series Rewriting using common denominators: |f(x)| = frac128|4x^2 + 21x + 28| Evaluating for i=1 to 5: 28 sum_i = 1^5 |f(i)| = 675 ### Pattern Recognition Substituting standard points like 0 and -x decouples symmetric multi-variable systems with maximum efficiency. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Maths: Relations and Functions

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Q6 jee_main_2024_31_jan_morning Composition of Functions
If f(x) = frac4x + 36x - 4, x neq frac23 and (fof)(x) = g(x), where g : mathbbR - left\frac23right\ to mathbbR - left\frac23right\, then (gogog)(4) is equal to
  • A. -frac1920
  • B. frac1920
  • C. -4
  • D. 4

Solution

### Core Logic f(x) = frac4x + 36x - 4 Compute g(x) = f(f(x)): g(x) = frac4left(frac4x + 36x - 4right) + 36left(frac4x + 36x - 4right) - 4 = frac16x + 12 + 18x - 1224x + 18 - 24x + 16 = frac34x34 = x ### Step 1: Composition Evaluation Since g(x) = x, g is the identity function. (gogog)(4) = g(g(g(4))) = 4 ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Maths: Relations and Functions
Q29 jee_main_2024_31_jan_morning Equivalence Relations
Let A = \1, 2, 3, 4\ and R = \(1, 2), (2, 3), (1, 4)\ be a relation on A. Let S be the equivalence relation on A such that R subset S and the number of elements in S is n. Then, the minimum value of n is
Numerical Answer. Answer: 16 to 16

Solution

### Core Logic S must be reflexive, symmetric, and transitive, containing (1,2), (2,3), and (1,4). Symmetric property forces (2,1), (3,2), (4,1) in S. Transitive property: (1,2) and (2,3) implies (1,3) in S. Symmetric implies (3,1) in S. (4,1) and (1,2) implies (4,2) in S. Symmetric implies (2,4) in S. (4,1) and (1,3) implies (4,3) in S. Symmetric implies (3,4) in S. ### Step 1: Universal Relation Since 1 is related to 2, 3, 4 and the relation is an equivalence relation (which creates partitions), all elements 1, 2, 3, and 4 must fall into the same single equivalence class. Thus, S must contain all possible ordered pairs in A times A. ### Step 2: Final Count Number of elements in A times A = 4 times 4 = 16. Minimum value of n is 16. ### Pattern Recognition If a relation connects all elements in a set to each other through a chain, its equivalence closure is the universal relation A times A. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Maths: Relations and Functions

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