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d-and f-Block Elements appeared 44 times across 3 years — 5.1% of Chemistry. This question is from Oxidizing Properties of KMnO4 and K2Cr2O7.

Year 2026 2025 2024 Total
Questions 10 17 17 44

Which of the following oxidation reactions are carried out by both K₂Cr₂O₇ and KMnO₄ in acidic medium? A. I^- arrow I₂ B. S²⁻ arrow S C. Fe²⁺ arrow Fe³⁺ D. I⁻ arrow IO₃⁻ E. S₂O₃²⁻ arrow SO₄²⁻ Choose the correct answer from the options given below:

Solution & Explanation

Core Logic

In an acidic medium, both K₂Cr₂O₇ and KMnO₄ act as strong oxidizing agents and carry out the following transformations:

  • A: Oxidize iodide to iodine: I^- arrow I₂
  • B: Oxidize sulfide to elemental sulfur: S²⁻ arrow S
  • C: Oxidize ferrous ions to ferric ions: Fe²⁺ arrow Fe³⁺
  • For reactions D and E:

  • Iodide is oxidized to iodate (IO₃^-) by KMnO₄ primarily in a neutral or faintly alkaline medium, not acidic.
  • Thiosulfate (S₂O₃²⁻) undergoes a disproportionation/precipitation reaction in acid rather than clean oxidation to sulfate by dichromate.
  • Thus, statements A, B, and C are valid for both under acidic conditions.

Pattern Recognition

Sees: Shared oxidation products in an acidic environment. Shortcut: Remember that I^- arrow IO₃^- is the signature reaction for alkaline permanganate, allowing quick elimination of choices containing D.

Chapter Mix

Class 12 Chemistry: The d-and f-Block Elements

Reference Study Guides

More The d-and f-Block Elements Previous-Year Questions — Page 9

Q76 jee_main_2024_30_jan_morning Transition Elements
Match List-I with List-II.
List-I (Species)List-II (Electronic distribution)
(A) Cr⁺²(I) 3d⁸
(B) Mn^+(II) 3d⁵4s¹
(C) Ni⁺²(III) 3d⁴
(D) V^+(IV) 3d³4s¹
Choose the correct answer from the options given below:
  • A. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  • B. (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  • C. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  • D. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Solution

Core Logic

Let's determine the electronic configuration for each species by first writing the neutral atom's configuration, and then removing electrons starting from the outermost 4s orbital.

(A) Cr (Z=24): [Ar] 3d⁵ 4s¹ arrow Cr²⁺: [Ar] 3d⁴ (B) Mn (Z=25): [Ar] 3d⁵ 4s² arrow Mn^+: [Ar] 3d⁵ 4s¹ (C) Ni (Z=28): [Ar] 3d⁸ 4s² arrow Ni²⁺: [Ar] 3d⁸ (D) V (Z=23): [Ar] 3d³ 4s² arrow V^+: [Ar] 3d³ 4s¹

Step 1: Match execution

A arrow III B arrow II C arrow I D arrow IV

Chapter Mix

Class 12 Chemistry: The d- and f-Block Elements

Q jee_main_2024_31_jan_evening Properties of Transition Metal Oxides
Choose the correct statements from the following A. Mn₂O₇ is an oil at room temperature B. V₂O₄ reacts with acid to give VO₂²⁺ C. CrO is a basic oxide D. V₂O₅ does not react with acid Choose the correct answer from the options given below:
  • A. A, B and D only
  • B. A and C only
  • C. A, B and C only
  • D. B and C only

Solution

Core Logic

(A) Mn₂O₇ is a covalent oxide and exists as a green oil at room temperature. (Correct) (B) V₂O₄ dissolves in acids to give VO²⁺ (vanadyl) salts, not VO₂²⁺. (Incorrect) (C) CrO has chromium in the +2 oxidation state. Lower oxidation state metal oxides are typically basic in nature. (Correct) (D) V₂O₅ is an amphoteric oxide; it reacts with both acids as well as bases. (Incorrect)

Step 1: Final Selection

Only statements A and C are correct, which corresponds to option (2).

Chapter Mix

Class 12 Chemistry: The d- and f-Block Elements

Q86 jee_main_2024_31_jan_evening Chromyl Chloride Test
In the reaction of potassium dichromate, potassium chloride and sulfuric acid (conc.), the oxidation state of the chromium in the product is (+) ________
Numerical Answer. Answer: 6 to 6

Solution

Related Formula
K₂Cr₂O₇(s) + 4KCl(s) + 6H₂SO₄(conc.) arrow 2CrO₂Cl₂(g) + 6KHSO₄ + 3H₂O
Core Logic

This reaction represents the Chromyl Chloride test used to detect the presence of chloride ions. When potassium dichromate is heated with a metal chloride in concentrated sulfuric acid, red vapors of chromyl chloride (CrO₂Cl₂) are evolved.

Step 1: Oxidation State Calculation

In chromyl chloride (CrO₂Cl₂): Let the oxidation state of Chromium be x. Oxygen is typically -2 and Chlorine is -1.

x + 2(-2) + 2(-1) = 0

x - 4 - 2 = 0 x = +6 Thus, the oxidation state of Chromium in the product is 6.

Chapter Mix

Class 12 Chemistry: The d- and f-Block Elements Class 11 Chemistry: Practical Chemistry

Q71 jee_main_2024_31_jan_morning Potassium Dichromate and Permanganate
Identify correct statements from below: A. The chromate ion is square planar. B. Dichromates are generally prepared from chromates. C. The green manganate ion is diamagnetic. D. Dark green coloured K₂MnO₄ disproportionates in a neutral or acidic medium to give permanganate. E. With increasing oxidation number of transition metal, ionic character of the oxides decreases. Choose the correct answer from the options given below:
  • A. B, C, D only
  • B. A, D, E only
  • C. A, B, C only
  • D. B, D, E only

Solution

Step 1: Statement A Analysis

CrO₄²⁻ (chromate ion) is tetrahedral, not square planar. Statement A is incorrect.

Step 2: Statement B Analysis

2Na₂CrO₄ + 2H^+ arrow Na₂Cr₂O₇ + 2Na^+ + H₂O. Dichromates are indeed prepared from chromates. Statement B is correct.

Step 3: Statement C Analysis

The green manganate ion (MnO₄²⁻) has manganese in the +6 oxidation state (3d¹). Thus, it contains 1 unpaired electron and is paramagnetic, not diamagnetic. Statement C is incorrect.

Step 4: Statement D Analysis

Dark green coloured K₂MnO₄ undergoes disproportionation in neutral or acidic media to yield permanganate (MnO₄^-) and manganese dioxide (MnO₂). Statement D is correct.

Step 5: Statement E Analysis

Fajans' rule dictates that as the oxidation state increases, polarizing power increases, leading to a decrease in ionic character (increase in covalent character). Statement E is correct.

Final Conclusion

The correct statements are B, D, and E.

Chapter Mix

Class 12 Chemistry: The d- and f-Block Elements

More The d-and f-Block Elements Questions — jee_main_2025_28_jan_morning

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