Solution
Core Logic
Let us identify the sequential chemical components via the chromyl chloride test pathway:
- Reactant A represents a dichromate salt such as K₂Cr₂O₇. Heating it with a metal chloride and concentrated sulfuric acid generates deep red chromyl chloride vapors (CrO₂Cl₂).
- Passing these vapors into sodium hydroxide dissolves them, producing yellow sodium chromate compound B (Na₂CrO₄).
- Acidifying the chromate solution dimerizes it into orange sodium dichromate compound C (Na₂Cr₂O₇).
Step 1: Structural Analysis of Dichromate
The dichromate ion (Cr₂O₇²⁻) consists of two tetrahedral chromium units sharing a single bridging oxygen atom (Cr-O-Cr). Each chromium atom retains 3 localized terminal oxygen atoms:
Total terminal 'O' atoms = 7 - 1 = 6Thus, the total count of terminal oxygen atoms present in compound C is 6.
Pattern Recognition
Shortcut: The chromyl chloride sequence moves from dichromate arrow chromate arrow dichromate. In the dichromate ion (Cr₂O₇²⁻), out of the 7 oxygen atoms, exactly 1 is bridging, leaving 7 - 1 = 6 terminal oxygen atoms.
Evaluation Rubric / Model Answer
6
Chapter Mix
Class 12 Chemistry: d- and f-Block Elements