Both acetaldehyde and acetone (individually) undergo which of the following reactions? A. Iodoform Reaction B. Cannizaro Reaction C. Aldol condensation D. Pollen's Test E. Clemmensen Reduction Choose the correct answer from the options given below:

### Related Formula CH_3-CHO + H_2N-NH-CO-NH_2 rightarrow CH_3-CH=N-NH-CO-NH_2 + H_2O$$CH_3-CHO + H_2N-NH-CO-NH_2 \rightarrow CH_3-CH=N-NH-CO-NH_2 + H_2O$$ ### Core Logic Ethanal (CH_3CHO$CH_3CHO$) reacts with semicarbazide (H_2N-NH-CO-NH_2$H_2N-NH-CO-NH_2$) via nucleophilic addition followed by elimination of water to form a semicarbazone. ### Step 1: Product Analysis The product is Ethanal semicarbazone: CH_3-CH=N-NH-CO-NH_2$CH_3-CH=N-NH-CO-NH_2$. Counting the nitrogen atoms in this structure: 1. The imine nitrogen (=N-$=N-$) 2. The amine nitrogen (-NH-$-NH-$) 3. The amide nitrogen (-NH_2$-NH_2$) Total = 3 Nitrogen atoms. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

### Core Logic The reaction of benzene with carbon monoxide (CO$CO$) and hydrogen chloride (HCl$HCl$) in the presence of anhydrous aluminium chloride (AlCl_3$AlCl_3$) and cuprous chloride (CuCl$CuCl$) to give benzaldehyde is known as the Gatterman-Koch reaction.

### Pattern Recognition CO + HCl rightarrow$CO + HCl \rightarrow$ Formyl chloride intermediate (in situ) with Lewis acid rightarrow$\rightarrow$ formylation of benzene. This is definitively the Gatterman-Koch formylation. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

### Core Logic The given reactant is p-hydroxybenzaldehyde, which contains both a phenolic -OH$-OH$ group (acidic) and an aldehyde group (electrophilic). When one equivalent of Grignard reagent (PhMgBr$PhMgBr$) is added, it behaves primarily as a strong base due to the presence of an acidic proton. Acid-base reactions are extremely fast compared to nucleophilic additions. The acidic phenolic -OH$-OH$ reacts with PhMgBr$PhMgBr$: PhMgBr + HO-C_6H_4-CHO rightarrow Ph-H (Benzene) + BrMg-O-C_6H_4-CHO$$PhMgBr + HO-C_6H_4-CHO \rightarrow Ph-H (Benzene) + BrMg-O-C_6H_4-CHO$$ Upon workup with aq. NH_4Cl$aq. NH_4Cl$, the phenoxide ion simply regenerates the starting p-hydroxybenzaldehyde. However, the question asks for the number of hydroxyl groups present in the formed product (Benzene).

The distinct product formed in the reaction is Benzene. Benzene has 0 hydroxyl groups. ### Pattern Recognition Whenever a Grignard reagent encounters a molecule with an acidic hydrogen (alcohol, phenol, amine, alkyne), it will invariably act as a base first. If only 1 equivalent is used, nucleophilic addition to carbonyls will NOT happen. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids Class 12 Chemistry: Alcohols, Phenols and Ethers