Let f:[0,3]rightarrow A be defined by f(x)=2x^3-15x^2+36x+7 and g:[0,infty)rightarrow B be defined by g(x)=fracx^2025x^2025+1. If both the functions are onto and S=\xin Z:xin Atext or xin B\, then n(S) is equal to:

Solution & Explanation

### Related Formula For a function to be onto, its Codomain must equal its Range. ### Core Logic First, find range A for f(x) = 2x^3 - 15x^2 + 36x + 7 over [0, 3]. Differentiating f(x): f'(x) = 6x^2 - 30x + 36 = 6(x^2 - 5x + 6) = 6(x-2)(x-3) Critical points are x=2 and x=3. Evaluate f(x) at boundary and critical points: - f(0) = 7 - f(2) = 2(8) - 15(4) + 36(2) + 7 = 16 - 60 + 72 + 7 = 35 - f(3) = 2(27) - 15(9) + 36(3) + 7 = 54 - 135 + 108 + 7 = 34 Thus, Range A = [7, 35]. ### Step 1: Find Range B for g(x) Now look at g(x) = fracx^2025x^2025+1 = 1 - frac1x^2025+1 over [0, infty). - At x = 0, g(0) = 0. - As x to infty, g(x) to 1. Since g(x) is continuous and monotonically strictly increasing, Range B = [0, 1). ### Step 2: Find the Integer Count of Union Set S S = \x in mathbbZ : x in A text or x in B\ = mathbbZ cap (A cup B) A cup B = [0, 1) cup [7, 35] The integers in this set are: - From [0, 1): x = 0 - From [7, 35]: x = 7, 8, 9, dots, 35 Total number of integers n(S): n(S) = 1 + (35 - 7 + 1) = 1 + 29 = 30 ### Pattern Recognition The condition 'or' means union. Be careful not to include integers between 1 and 6 since they are not present in either continuous range segment. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Mathematics: Functions Class 12 Mathematics: Application of Derivatives

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More Functions Previous-Year Questions — Page 10

Q6 jee_main_2024_31_jan_morning Composition of Functions
If f(x) = frac4x + 36x - 4, x neq frac23 and (fof)(x) = g(x), where g : mathbbR - left\frac23right\ to mathbbR - left\frac23right\, then (gogog)(4) is equal to
  • A. -frac1920
  • B. frac1920
  • C. -4
  • D. 4

Solution

### Core Logic f(x) = frac4x + 36x - 4 Compute g(x) = f(f(x)): g(x) = frac4left(frac4x + 36x - 4right) + 36left(frac4x + 36x - 4right) - 4 = frac16x + 12 + 18x - 1224x + 18 - 24x + 16 = frac34x34 = x ### Step 1: Composition Evaluation Since g(x) = x, g is the identity function. (gogog)(4) = g(g(g(4))) = 4 ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Maths: Relations and Functions
Q29 jee_main_2024_31_jan_morning Equivalence Relations
Let A = \1, 2, 3, 4\ and R = \(1, 2), (2, 3), (1, 4)\ be a relation on A. Let S be the equivalence relation on A such that R subset S and the number of elements in S is n. Then, the minimum value of n is
Numerical Answer. Answer: 16 to 16

Solution

### Core Logic S must be reflexive, symmetric, and transitive, containing (1,2), (2,3), and (1,4). Symmetric property forces (2,1), (3,2), (4,1) in S. Transitive property: (1,2) and (2,3) implies (1,3) in S. Symmetric implies (3,1) in S. (4,1) and (1,2) implies (4,2) in S. Symmetric implies (2,4) in S. (4,1) and (1,3) implies (4,3) in S. Symmetric implies (3,4) in S. ### Step 1: Universal Relation Since 1 is related to 2, 3, 4 and the relation is an equivalence relation (which creates partitions), all elements 1, 2, 3, and 4 must fall into the same single equivalence class. Thus, S must contain all possible ordered pairs in A times A. ### Step 2: Final Count Number of elements in A times A = 4 times 4 = 16. Minimum value of n is 16. ### Pattern Recognition If a relation connects all elements in a set to each other through a chain, its equivalence closure is the universal relation A times A. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Maths: Relations and Functions

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