jee_main_2025_08_april_evening - Chemical Thermodynamics Topics

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QUESTION #0 Resonance Energy
Resonance in an textX_2textY molecule is represented as follows: textX = textX = textY longleftrightarrow textX equiv textX^+ - textY^- The experimental enthalpy of formation for gaseous textX_2textY is given by the reaction: textX equiv textX(g) + frac12textY = textY(g) longrightarrow textX_2textY(g) quad Delta H_f(textexp) = 80 text kJ mol^-1 Calculate the magnitude of the resonance energy of textX_2textY in textkJ mol^-1 (as the nearest integer value). **Given bond energies:** * textX equiv textX = 940 text kJ mol^-1 * textX = textX = 410 text kJ mol^-1 * textY = textY = 500 text kJ mol^-1 * textX = textY = 602 text kJ mol^-1 Valence settings: textX : 3, textY : 2
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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)
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