jee_main_2025_08_april_evening - Chemical Thermodynamics Topics

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QUESTION #0 Resonance Energy
Resonance in an X₂Y molecule is represented as follows: X = X = Y X ≡ X^+ - Y^- The experimental enthalpy of formation for gaseous X₂Y is given by the reaction: X ≡ X(g) + (1)/(2)Y = Y(g) X₂Y(g) Δ Hf(exp) = 80 kJ mol⁻¹ Calculate the magnitude of the resonance energy of X₂Y in kJ mol⁻¹ (as the nearest integer value). **Given bond energies:** * X ≡ X = 940 kJ mol⁻¹ * X = X = 410 kJ mol⁻¹ * Y = Y = 500 kJ mol⁻¹ * X = Y = 602 kJ mol⁻¹ Valence settings: X : 3, Y : 2
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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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