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Matrices and Determinants appeared 59 times across 3 years — 6.8% of Mathematics. This question is from Properties of Adjoint.

Year 2026 2025 2024 Total
Questions 16 27 16 59

Let A be a 3 × 3 matrix such that |adj(adj(adj A))| = 81. If S = n in Z : (|adj(adj A)|)((n - 1)²)/(2) = |A|3n² - 5n - 4, then Σn in S |An² + n| is equal to

Solution & Explanation

Related Formula

For any n × n matrix A, the determinant properties of adjoints scale iteratively as follows:

|adj A| = |A|ⁿ⁻¹ |adj(adj A)| = |A|(n-1)² |adj(adj(adj A))| = |A|(n-1)³
Core Logic

Since A is a 3 × 3 matrix (n=3):

|adj(adj(adj A))| = |A|(3-1)³ = |A|⁸ = 81 |A|⁸ = 3⁴ |A|² = 3 |A| = 31/2 = √(3)

Now look at the power base for the equation: |adj(adj A)| = |A|(3-1)² = |A|⁴. Substitute this into the matching requirement equation set:

(|A|⁴)((n-1)²)/(2) = |A|3n² - 5n - 4 |A|2(n-1)² = |A|3n² - 5n - 4

Equating exponents since bases are identical:

2(n - 1)² = 3n² - 5n - 4 2(n² - 2n + 1) = 3n² - 5n - 4 2n² - 4n + 2 = 3n² - 5n - 4

n² - n - 6 = 0

Step 1: Solve for Exponent Parameter

Factoring the quadratic parameter relation:

(n - 3)(n + 2) = 0 n = 3 or n = -2

Both choices are valid integers, so the set S = -2, 3.

Step 2: Calculate the Target Summation

We need to evaluate Σnin S |An² + n| = |A(-2)² + (-2)| + |A(3)² + 3|:

  • For n = -2, n² + n = 4 - 2 = 2 |A²| = |A|² = 3
  • For n = 3, n² + n = 9 + 3 = 12 |A¹²| = |A|¹² = (√(3))¹² = 3⁶ = 729
  • Summing these evaluated values:

Total = 3 + 729 = 732
Pattern Recognition

Always remember that |A^k| = |A|^k. Calculating determinant transformations directly as scalar power factors first prevents rendering high order numerical values prematurely.

Chapter Mix

Class 12 Mathematics: Matrices and Determinants

More Matrices and Determinants Previous-Year Questions — Page 9

Q jee_main_2025_29_jan_morning Properties of Determinants
Let M and m respectively be the maximum and the minimum values of f (x) = | arrayc c c 1 + ^ 2 x & ^ 2 x & 4 4 x ^ 2 x & 1 + ^ 2 x & 4 4 x ^ 2 x & ^ 2 x & 1 + 4 4 x array |, x in R Then M⁴ -m⁴ is equal to :
  • A. 1280
  • B. 1295
  • C. 1040
  • D. 1215

Solution

Related Formula
² x + ² x = 1 -1 ≤ 4x ≤ 1
Core Logic

Apply the row operations R₂ → R₂ - R₁ and R₃ → R₃ - R₁ to simplify the determinant:

f(x) = | arrayc c c 1 + ^ 2 x & ^ 2 x & 4 4 x -1 & 1 & 0 -1 & 0 & 1 array |
Step 1: Expand the Determinant

Expanding along the first row:

f(x) = (1 + ² x)(1 - 0) - ² x(-1 - 0) + 4 4x(0 - (-1)) f(x) = 1 + ² x + ² x + 4 4x

Since ² x + ² x = 1, we get:

f(x) = 2 + 4 4x
Step 2: Find Maximum and Minimum Values

The range of 4x is [-1, 1].

M = 2 + 4(1) = 6 m = 2 + 4(-1) = -2
Step 3: Calculate M⁴ - m⁴
M⁴ - m⁴ = 6⁴ - (-2)⁴ = 1296 - 16 = 1280
Pattern Recognition

Look for repeated structures or cyclic additions in rows. Subtracting rows quickly creates zeros, reducing complex trigonometric matrices into elementary algebraic expressions.

Chapter Mix

Class 12 Mathematics: Matrices and Determinants Class 11 Mathematics: Trigonometric Functions

Q jee_main_2025_29_jan_morning Cofactors and Determinant Value
Let A = [aᵢⱼ] = bmatrix ₅ 128 & ₄ 5 ₅ 8 & ₄ 25 bmatrix . If Aᵢⱼ is the cofactor of aᵢⱼ , Cᵢⱼ = Σk=1² aik Ajk , 1 ≤ i, j ≤ 2 , and C = [Cᵢⱼ] , then 8|C| is equal to:
  • A. 262
  • B. 288
  • C. 242
  • D. 222

Solution

Related Formula
Σk aik Ajk = δᵢⱼ |A| C = bmatrix |A| & 0 0 & |A| bmatrix |C| = |A|²
Core Logic

Evaluate the determinant of matrix A:

|A| = ( ₅ 128)( ₄ 25) - ( ₄ 5)( ₅ 8)

Using change of base rules:

|A| = (7 ₅ 2)(2 ₄ 5) - ((1)/(2) ₂ 5)(3 ₅ 2) |A| = 14( ₅ 2 · (1)/(2) ₂ 5) - (3)/(2) = 7 - 1.5 = 5.5 = (11)/(2)
Step 1: Compute |C| and evaluate response target

Since matrix properties dictate |C| = |A|²:

|C| = ((11)/(2))² = (121)/(4)

Evaluate targeted multiplier:

8|C| = 8 × (121)/(4) = 2 × 121 = 242
Pattern Recognition

Recognize the core cofactor theorem identity instantly: multiplying rows by cofactors of other rows creates zero elements, yielding basic diagonal scalar structures matching matrix attributes.

Chapter Mix

Class 12 Mathematics: Matrices and Determinants

Q jee_main_2025_29_jan_morning Matrix Powers
Let S = | m in Z : Am² + A^m = 3I - A⁻⁶ | , where A = bmatrix 2 & -1 1 & 0 bmatrix . Then n(S) is equal to
Numerical Answer. Answer: 2

Solution

Related Formula
Inductive formulation for exponent powers of a pattern matrix
Core Logic

Evaluate lower power forms of A to establish inductive sequence patterns:

A = bmatrix 2 & -1 1 & 0 bmatrix, A² = bmatrix 3 & -2 2 & -1 bmatrix, A³ = bmatrix 4 & -3 3 & -2 bmatrix

This cleanly establishes general power state rule configuration expression:

A^m = bmatrix m+1 & -m m & -m+1 bmatrix
Step 1: Setup Matrix Power Equation

Using the pattern, find expressions for terms:

A⁶ = bmatrix 7 & -6 6 & -5 bmatrix, A⁻⁶ = (A⁶)⁻¹ = bmatrix -5 & 6 -6 & 7 bmatrix

Substitute into the targeted equation block:

Am² + A^m = 3 bmatrix 1 & 0 0 & 1 bmatrix - bmatrix -5 & 6 -6 & 7 bmatrix = bmatrix 8 & -6 6 & -4 bmatrix
Step 2: Equate Corresponding Elements

From the bottom-left entry [2,1]:

m² + m = 6 m² + m - 6 = 0 (m+3)(m-2) = 0 m = -3, 2

Both integer states satisfy all matrix components seamlessly. Therefore, the number of elements n(S) = 2.

Pattern Recognition

Always calculate first 2–3 matrix powers to spot linear arithmetic trends across specific cell values (m+1, -m), avoiding tedious full Cayley-Hamilton character expansions.

Chapter Mix

Class 12 Mathematics: Matrices

Q3 jee_main_2024_01_february_morning Properties of Determinants
If A= bmatrix√(2) & 1 -1 & √(2) bmatrix, B= bmatrix1 & 0 1 & 1 bmatrix, C=ABAT and X=ATC²A, then X is equal to:
  • A. 243
  • B. 729
  • C. 27
  • D. 891

Solution

Related Formula

Properties of Determinants:

  • (AB) = (A) · (B)
  • (A^T) = (A)
  • (Aⁿ) = ( (A))ⁿ
Core Logic

First, find the determinant of matrix A and matrix B:

(A) = |A| = vmatrix√(2) & 1 -1 & √(2) vmatrix = (√(2))(√(2)) - (1)(-1) = 2 + 1 = 3 (B) = |B| = vmatrix1 & 0 1 & 1 vmatrix = (1)(1) - (0)(1) = 1
Step 1: Calculate determinant of C

Given C = ABAT, we calculate its determinant:

(C) = (ABAT) = (A) · (B) · (AT)

Using (A^T) = (A) = 3:

(C) = 3 · 1 · 3 = 9
Step 2: Calculate determinant of X

Given X = ATC²A, we determine |X|:

(X) = |ATC²A| = |AT| · |C²| · |A| (X) = |A| · |C|² · |A| = |A|² · |C|²

Substitute the values |A| = 3 and |C| = 9:

(X) = (3)² · (9)² = 9 · 81 = 729
Pattern Recognition

Sees: Transpose and multiplication operations nested inside a determinant statement. Shortcut: Never explicitly compute product matrices like ABA^T or A^TC²A. Apply the distributive identity of determinants |XYZ| = |X||Y||Z| entirely to work strictly with scalar multiplication.

Chapter Mix

Class 12 Mathematics: Matrices and Determinants

Q12 jee_main_2024_01_february_morning System of Linear Equations
If the system of equations 2x+3y-z=5 x+α y+3z=-4 3x-y+β z=7 has infinitely many solutions, then 13 α β is equal to:
  • A. 1110
  • B. 1120
  • C. 1210
  • D. 1220

Solution

Related Formula

For a system of linear equations representing planes to have infinitely many solutions, the planes must belong to a single family sharing a common line of intersection:

P₁ = k₁ P₂ + k₂ P₃
Core Logic

Let the planes be defined as:

  • P₁: 2x + 3y - z - 5 = 0
  • P₂: x + α y + 3z + 4 = 0
  • P₃: 3x - y + β z - 7 = 0
  • Expressing P₁ as a linear combination of P₂ and P₃:

2x + 3y - z - 5 = k₁(x + α y + 3z + 4) + k₂(3x - y + β z - 7)
Step 1: Evaluate parameters k1 and k2

Comparing the coefficients of x and the constant terms on both sides:

  • For x:
k₁ + 3k₂ = 2 (1)
  • For the constants:
4k₁ - 7k₂ = -5 (2)

Multiplying equation (1) by 4 gives 4k₁ + 12k₂ = 8. Subtracting equation (2) from this result:

(4k₁ + 12k₂) - (4k₁ - 7k₂) = 8 - (-5) 19k₂ = 13 k₂ = (13)/(19)

Substituting k₂ back into equation (1):

k₁ + 3((13)/(19)) = 2 k₁ = 2 - (39)/(19) = -(1)/(19)
Step 2: Calculate alpha, beta and final product

Comparing coefficients for y and z:

  • For y:
k₁α - k₂ = 3 -(1)/(19)α - (13)/(19) = 3 -α - 13 = 57 α = -70
  • For z:
3k₁ + k₂β = -1 3(-(1)/(19)) + (13)/(19)β = -1 -3 + 13β = -19 13β = -16 β = -(16)/(13)

Now, compute 13 α β:

13 α β = 13 × (-70) × (-(16)/(13)) = 70 × 16 = 1120
Pattern Recognition

Sees: Infinite solution framework for three linear planes. Shortcut: Using the family of planes equation is significantly less prone to fractional algebraic mistakes compared to establishing Cramer's rule determinants (D = Dₓ = Dy = Dz = 0).

Chapter Mix

Class 12 Mathematics: Matrices and Determinants

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