Related Formula
For any n × n$n \times n$ matrix A$A$, the determinant properties of adjoints scale iteratively as follows:
|adj A| = |A|ⁿ⁻¹$$|\text{adj } A| = |A|^{n-1}$$
|adj(adj A)| = |A|(n-1)²$$|\text{adj(adj } A)| = |A|^{(n-1)^2}$$
|adj(adj(adj A))| = |A|(n-1)³$$|\text{adj(adj(adj } A))| = |A|^{(n-1)^3}$$
Core Logic
Since A$A$ is a 3 × 3$3 \times 3$ matrix (n=3$n=3$):
|adj(adj(adj A))| = |A|(3-1)³ = |A|⁸ = 81$$|\text{adj(adj(adj } A))| = |A|^{(3-1)^3} = |A|^8 = 81$$
|A|⁸ = 3⁴ |A|² = 3 |A| = 31/2 = √(3)$$|A|^8 = 3^4 \implies |A|^2 = 3 \implies |A| = 3^{1/2} = \sqrt{3}$$
Now look at the power base for the equation: |adj(adj A)| = |A|(3-1)² = |A|⁴$|\text{adj(adj } A)| = |A|^{(3-1)^2} = |A|^4$.
Substitute this into the matching requirement equation set:
(|A|⁴)((n-1)²)/(2) = |A|3n² - 5n - 4$$\left(|A|^4\right)^{\frac{(n-1)^2}{2}} = |A|^{3n^2 - 5n - 4}$$
|A|2(n-1)² = |A|3n² - 5n - 4$$|A|^{2(n-1)^2} = |A|^{3n^2 - 5n - 4}$$
Equating exponents since bases are identical:
2(n - 1)² = 3n² - 5n - 4$$2(n - 1)^2 = 3n^2 - 5n - 4$$
2(n² - 2n + 1) = 3n² - 5n - 4$$2(n^2 - 2n + 1) = 3n^2 - 5n - 4$$
2n² - 4n + 2 = 3n² - 5n - 4$$2n^2 - 4n + 2 = 3n^2 - 5n - 4$$
n² - n - 6 = 0$n^2 - n - 6 = 0$
Step 1: Solve for Exponent Parameter
Factoring the quadratic parameter relation:
(n - 3)(n + 2) = 0 n = 3 or n = -2$$(n - 3)(n + 2) = 0 \implies n = 3 \quad \text{or} \quad n = -2$$
Both choices are valid integers, so the set S = -2, 3$S = \{-2, 3\}$.
Step 2: Calculate the Target Summation
We need to evaluate Σnin S |An² + n| = |A(-2)² + (-2)| + |A(3)² + 3|$\sum_{n\in S} |A^{n^2 + n}| = |A^{(-2)^2 + (-2)}| + |A^{(3)^2 + 3}|$:
Total = 3 + 729 = 732$$\text{Total} = 3 + 729 = 732$$
Pattern Recognition
Always remember that |A^k| = |A|^k$|A^k| = |A|^k$. Calculating determinant transformations directly as scalar power factors first prevents rendering high order numerical values prematurely.
Chapter Mix
Class 12 Mathematics: Matrices and Determinants