Given below are the pairs of group 13 elements showing their relation in terms of atomic radius: (B < Al), (Al < Ga), (Ga < In) and (In < Tl) Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius (M^3+) than the other one. The atomic number of the element (X) is:

Solution & Explanation

### Core Logic Let's evaluate the anomalies within Group 13 trends: * **Atomic Radius Order:** Due to the poor shielding effect of the filled 3d electron subshell in Gallium (transition contraction), its outer valence shell experiences a stronger nuclear pull. Consequently, the atomic radius sequence exhibits an inversion: textCorrect Atomic Size: B < Ga < Al < In < Tl Therefore, the pair (Al < Ga) provided in the problem statement is incorrect. * **Ionic Radius Order (M^3+):** In the fully ionized +3 configuration state, the transition contraction anomaly is overridden by standard shell count physics. The ionic radius follows the uniform down-the-group trend: Al^3+ < Ga^3+ Hence, Gallium (Ga) has the larger ionic radius between the two elements. Its atomic number is 31. ### Pattern Recognition Transition contraction heavily distorts the *atomic* radius profile of Gallium, but standard descending size progression rules are fully restored when evaluating the *ionic* M^3+ radius profile. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Classification of Elements and Periodicity in Properties Class 12 Chemistry: The p-Block Elements

Reference Study Guides

More Classification of Elements and Periodicity in Properties Previous-Year Questions — Page 6

Q84 jee_main_2024_30_jan_morning IUPAC Nomenclature for Elements > 100
If IUPAC name of an element is "Unununnium" then the element belongs to nth group of periodic table. The value of n is
Numerical Answer. Answer: 11 to 11

Solution

### Core Logic Decode the IUPAC name "Unununnium" into its atomic number. Un = 1 Un = 1 Un = 1 Suffix = ium So, the atomic number is 111. ### Step 1: Finding group number For d-block elements with Z > 100, the group number is the last two digits of the atomic number. Since Z = 111, the element belongs to group 11 (the Copper group). ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Classification of Elements and Periodicity in Properties
Q80 jee_main_2024_31_jan_evening Periodic Trends in Properties
Consider the following elements.
Group downarrowA^primeB^prime rightarrow Period
C^primeD^prime
Which of the following is/are true about A^prime, B^prime, C^prime and D^prime? A. Order of atomic radii: B^prime < A^prime < D^prime < C^prime B. Order of metallic character: B^prime < A^prime < D^prime < C^prime C. Size of the element: D^prime < C^prime < B^prime < A^prime D. Order of ionic radii: B^prime + < A^prime + < D^prime + < C^prime + Choose the correct answer from the options given below:
  • A. text1. A only
  • B. text2. A, B and D only
  • C. text3. A and B only
  • D. text4. B, C and D only

Solution

### Core Logic From the grid layout, A^prime and B^prime are in the same period (left to right), while C^prime and D^prime are below them in the next period. In general, moving along a period from left to right, size decreases and metallic character decreases. Moving down a group, size increases and metallic character increases. Atomic Radii / Size: B^prime < A^prime (across period) D^prime < C^prime (across period) A^prime < C^prime and B^prime < D^prime (down the group) Combining them: B^prime < A^prime < D^prime < C^prime. (Statement A is correct, C is incorrect). Metallic Character: B^prime < A^prime and D^prime < C^prime Overall trend follows size closely for these blocks: B^prime < A^prime < D^prime < C^prime. (Statement B is correct). Ionic Radii (+ ions): Follows the same basic trend as atomic radii: B^prime + < A^prime + < D^prime + < C^prime +. (Statement D is correct). ### Step 1: Final Selection Statements A, B, and D are correct. Statement C contradicts A, so it is incorrect. Option 2 is the right choice. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Classification of Elements and Periodicity in Properties
Q70 jee_main_2024_31_jan_morning Electron Gain Enthalpy
The correct sequence of electron gain enthalpy of the elements listed below is A. Ar B. Br C. F D. S Choose the most appropriate from the options given below:
  • A. C > B > D > A
  • B. A > D > B > C
  • C. A > D > C > B
  • D. D > C > B > A

Solution

### Core Logic Electron gain enthalpy (Delta_egH) values are considered with their signs when ordering from largest to smallest algebraically.
ElementDelta_egH text (kJ/mol)
F-333
S-200
Br-325
Ar+96
Arranging these algebraically from highest to lowest: +96 > -200 > -325 > -333 Thus, Ar > S > Br > F, which corresponds to A > D > B > C. ### Pattern Recognition Noble gases always have positive electron gain enthalpies (highest algebraically). Halogens have highly negative values (lowest algebraically). Fluorine is highly negative, Bromine is slightly less negative. Sulfur sits in between. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Classification of Elements and Periodicity in Properties

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