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Given below are the pairs of group 13 elements showing their relation in terms of atomic radius: (B < Al), (Al < Ga), (Ga < In) and (In < Tl) Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius (M^3+) than the other one. The atomic number of the element (X) is:

Solution & Explanation

### Core Logic Let's evaluate the anomalies within Group 13 trends: * **Atomic Radius Order:** Due to the poor shielding effect of the filled 3d electron subshell in Gallium (transition contraction), its outer valence shell experiences a stronger nuclear pull. Consequently, the atomic radius sequence exhibits an inversion: textCorrect Atomic Size: B < Ga < Al < In < Tl Therefore, the pair (Al < Ga) provided in the problem statement is incorrect. * **Ionic Radius Order (M^3+):** In the fully ionized +3 configuration state, the transition contraction anomaly is overridden by standard shell count physics. The ionic radius follows the uniform down-the-group trend: Al^3+ < Ga^3+ Hence, Gallium (Ga) has the larger ionic radius between the two elements. Its atomic number is 31. ### Pattern Recognition Transition contraction heavily distorts the *atomic* radius profile of Gallium, but standard descending size progression rules are fully restored when evaluating the *ionic* M^3+ radius profile. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Classification of Elements and Periodicity in Properties Class 12 Chemistry: The p-Block Elements

More Classification of Elements and Periodicity in Properties Previous-Year Questions — Page 4

Q45 2025 Periodic Trends in Physical and Chemical Properties
Given below are two statements : Statement (I) : The radii of isoelectronic species increases in the order: mathrm M g ^ 2 + < mathrm N a ^ + < mathrm F ^ - < mathrm O ^ 2 - Statement (II) : The magnitude of electron gain enthalpy of halogen decreases in the order: mathrm C l > mathrm F > mathrm B r > mathrm I
  • A. Statement I is incorrect but Statement II is correct
  • B. Both Statement I and Statement II are incorrect.
  • C. Statement I is correct but Statement II is incorrect
  • D. Both Statement I and Statement II are correct

Solution

### Related Formula textIonic Radius propto frac1textNuclear Charge (Z) quad text(for Isoelectronic series) ### Core Logic Evaluating each statement systematically : * Statement (I) is correct: mathrmMg^2+, mathrmNa^+, mathrmF^-, mathrmO^2- all possess exactly 10 electrons (isoelectronic). As the positive nuclear charge decreases (Z = 12 for mathrmMg down to Z = 8 for mathrmO), the nucleus exerts less pull on the electron cloud, causing the ionic radius to increase : mathrmMg^2+ < mathrmNa^+ < mathrmF^- < mathrmO^2- * Statement (II) is correct: Chlorine has a higher electron gain enthalpy magnitude than fluorine due to lower electron-electron repulsion in its larger 3p orbital. The standard halogen trend follows: mathrmCl > mathrmF > mathrmBr > mathrmI Thus, both statements are correct. ### Pattern Recognition For species with the same number of electrons, a higher negative charge always leads to a larger electron cloud radius due to reduced nuclear traction. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Classification of Elements and Periodicity in Properties

More Classification of Elements and Periodicity in Properties Questions — jee_main_2025_04_april_morning

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