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If alpha is a root of the equation x^2 + x + 1 = 0 and sum_k=1^nleft(alpha^k + frac1alpha^kright)^2 = 20, then n is equal to

Numerical Answer Type:
Enter a numerical value Answer: 11 to 11 +4 marks

Solution & Explanation

### Core Logic The equation x^2 + x + 1 = 0 has complex roots which are the non-real cube roots of unity. Thus, we can set alpha = omega (where omega^3 = 1 and 1 + omega + omega^2 = 0). Let's analyze the general term block T_k = left(omega^k + frac1omega^kright)^2: T_k = left(omega^k + omega^-kright)^2 = omega^2k + omega^-2k + 2 = omega^2k + omega^k + 2 Because omega^k is periodic with period 3, let's examine the values of T_k for different values of k: - If k is a multiple of 3 (k=3m): omega^2k = 1, omega^k = 1 implies T_k = 1 + 1 + 2 = 4. - If k is not a multiple of 3 (k=3m+1 or 3m+2): omega^2k + omega^k = -1 implies T_k = -1 + 2 = 1. ### Step 1: Evaluating periodic blocks Every block of three consecutive terms (k = 1, 2, 3) contributes exactly: textSum of a block = 1 + 1 + 4 = 6 We want the total summation to equal 20. Let's divide 20 by our block value 6: 20 = 3 times 6 + 2 This means the sum must consist of 3 full periodic blocks plus additional terms that add up to 2. ### Step 2: Determining the final term count n The number of terms in 3 full blocks is 3 times 3 = 9 terms, giving a sum of 18. To get the remaining value of 2, we look at the next terms: - Term 10 (k=10, not a multiple of 3) adds 1 implies textTotal = 18 + 1 = 19. - Term 11 (k=11, not a multiple of 3) adds 1 implies textTotal = 19 + 1 = 20. Hence, the series terminates exactly at n = 11. ### Pattern Recognition Whenever complex roots of unity or cyclic properties show up inside series sums, group terms into blocks based on the underlying period length (3 here) to convert large sums into simple modular arithmetic arithmetic calculations. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Mathematics: Complex Numbers Class 11 Mathematics: Sequences and Series

Reference Study Guides

More Complex Numbers Previous-Year Questions — Page 2

Q64 2025 Roots of Quadratic Equations in Complex Fields
Let zin mathbbC be such that fracz^2 + 3iz - 2 + i = 2 + 3i[cite: 627, 629]. Then the sum of all possible values of z^2 is[cite: 630]:
  • A. 19 - 2i
  • B. -19 - 2i
  • C. 19 + 2i
  • D. -19 + 2i

Solution

### Related Formula For a quadratic system equation az^2+bz+c=0 with roots z_1, z_2: 1. z_1 + z_2 = -b/a 2. z_1 z_2 = c/a 3. z_1^2 + z_2^2 = (z_1+z_2)^2 - 2z_1z_2 ### Core Logic Cross-multiply the denominators to configure a linear equation layout [cite: 1355]: z^2 + 3i = (z - 2 + i)(2 + 3i) [cite: 1355] z^2 + 3i = z(2 + 3i) + (-2 + i)(2 + 3i) [cite: 1355] z^2 + 3i = z(2 + 3i) - 4 - 6i + 2i - 3 = z(2 + 3i) - 7 - 4i [cite: 1355] Formulate the classic quadratic representation layout [cite: 1356]: z^2 - z(2 + 3i) + 7 + 7i = 0 [cite: 1356] ### Step 1: Summing the squared roots Identify coefficients from the structural template [cite: 1357]: z_1 + z_2 = 2 + 3i z_1 z_2 = 7 + 7i Evaluate sum of possible squared values (z_1^2 + z_2^2) [cite: 1357]: z_1^2 + z_2^2 = (z_1 + z_2)^2 - 2z_1 z_2 [cite: 1357] = (2 + 3i)^2 - 2(7 + 7i) [cite: 1357] = (4 - 9 + 12i) - (14 + 14i) = -5 + 12i - 14 - 14i [cite: 1357] = -19 - 2i [cite: 1358] ### Pattern Recognition The question asks for the sum of values of z^2, meaning z_1^2 + z_2^2. Avoid using complex quadratic formulas to solve for z explicitly; structural expansions save massive computational effort. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Mathematics: Complex Numbers
Q55 2025 Properties of Complex Numbers
Let the product of omega_1 = (8 + mathrmi) sin theta + (7 + 4 mathrmi) cos theta and omega_2 = (1 + 8 mathrmi) sin theta + (4 + 7 mathrmi) cos theta be alpha +mathrmibeta, mathrmi = sqrt-1. Let p and q be the maximum and the minimum values of alpha +beta respectively.
  • A. 140
  • B. 130
  • C. 160
  • D. 150

Solution

### Core Logic Let's expand the terms by grouping real and imaginary parts explicitly: omega_1 = (8sintheta + 7costheta) + i(sintheta + 4costheta) omega_2 = (sintheta + 4costheta) + i(8sintheta + 7costheta) Notice that if we let u = 8sintheta + 7costheta and v = sintheta + 4costheta, then: omega_1 = u + iv quad textand quad omega_2 = v + iu ### Step 1: Calculating the Product Multiplying omega_1 and \omega_2: omega_1omega_2 = (u + iv)(v + iu) = uv + iu^2 + iv^2 - uv = i(u^2 + v^2) Since the product is given as alpha + ibeta: alpha = 0 beta = u^2 + v^2 = (8sintheta + 7costheta)^2 + (sintheta + 4costheta)^2 ### Step 2: Simplifying the expression for alpha + beta Expanding the terms for beta: beta = (64sin^2theta + 49cos^2theta + 112sinthetacostheta) + (sin^2theta + 16cos^2theta + 8sinthetacostheta) alpha + beta = 0 + beta = 65sin^2theta + 65cos^2theta + 120sinthetacostheta Using the identity sin^2theta + cos^2theta = 1 and 2sinthetacostheta = sin 2theta: alpha + beta = 65 + 60sin 2theta ### Step 3: Max and Min Extrema Analysis Since -1 le sin 2theta le 1: textMaximum value p = 65 + 60(1) = 125 textMinimum value q = 65 + 60(-1) = 5 Sum of maximum and minimum bounds equals: p + q = 125 + 5 = 130 ### Pattern Recognition Observe the symmetric structure in complex variables: (u+iv) and (v+iu). Their product structurally completely cancels out the real component, saving you from a highly messy component expansion. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Mathematics: Complex Numbers Class 11 Mathematics: Trigonometric Functions
Q73 2025 Geometry of Complex Numbers
Let A = \z in mathbbC : |z - 2 - i| = 3\, B = \z in mathbbC : operatornameRe(z - iz) = 2\ and S = A cap B. Then sum_z in S |z|^2 is equal to
Numerical Answer. Answer: 22 to 22

Solution

### Related Formula Magnitude squared representation: |z|^2 = x^2 + y^2 quad textfor z = x + iy ### Core Logic Convert complex sets into Cartesian forms by setting z = x + iy: Set A: |(x-2) + i(y-1)| = 3 implies (x-2)^2 + (y-1)^2 = 9 quad dots (1) Set B: z - iz = (x+iy) - i(x+iy) = (x+y) + i(y-x). operatornameRe(z - iz) = 2 implies x + y = 2 implies y = 2 - x quad dots (2) ### Step 1: Solve System Algebraically Substitute (2) into (1): (x - 2)^2 + (2 - x - 1)^2 = 9 implies (x - 2)^2 + (1 - x)^2 = 9 x^2 - 4x + 4 + 1 - 2x + x^2 = 9 implies 2x^2 - 6x - 4 = 0 implies x^2 - 3x - 2 = 0 Roots are x_1,2 = frac3 pm sqrt172. Correspondingly, y = 2 - x implies y_1,2 = frac1 mp sqrt172. ### Step 2: Evaluate Sum of Square Magnitudes Since S consists of the two intersection points z_1, z_2: sum_z in S |z|^2 = (x_1^2 + y_1^2) + (x_2^2 + y_2^2) = (x_1^2 + x_2^2) + (y_1^2 + y_2^2) Using identities from quadratic equation x^2 - 3x - 2 = 0 (x_1+x_2 = 3, x_1x_2 = -2): x_1^2 + x_2^2 = (3)^2 - 2(-2) = 13. Since y = 2-x, y^2 = 4 - 4x + x^2 implies y_1^2 + y_2^2 = 8 - 4(3) + 13 = 9. sum_z in S |z|^2 = 13 + 9 = 22 ### Pattern Recognition Avoid explicitly using radical root approximations. Summing symmetric expressions directly through standard Vieta coefficient sum shortcuts preserves clean fractions. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Mathematics: Complex Numbers and Quadratic Equations
Q61 2025 Locus of a Complex Number
If the locus of z in C, such that operatorname R e left(frac z - 12 z + mathrm iright) + operatorname R e left(frac bar z - 12 bar z - mathrm iright) = 2, is a circle of radius r and center (a, b) then frac15abr^2 is equal to:
  • A. 24
  • B. 12
  • C. 18
  • D. 16

Solution

### Related Formula For a complex number w, operatornameRe(w) = operatornameRe(barw). Hence: operatornameRe(w) + operatornameRe(barw) = 2operatornameRe(w) ### Core Logic Notice that fracbarz - 12barz - i is the exact complex conjugate of fracz - 12z + i. Thus, the given equation simplifies directly via complex identities to: 2operatornameReleft(fracz - 12z + iright) = 2 implies operatornameReleft(fracz - 12z + iright) = 1 ### Step 1: Substitute z = x + iy Let z = x + iy: frac(x - 1) + iy2x + i(2y + 1) To find the real part, multiply numerator and denominator by the conjugate of the denominator: operatornameReleft[ frac((x - 1) + iy)(2x - i(2y + 1))4x^2 + (2y + 1)^2 right] = 1 frac2x(x - 1) + y(2y + 1)4x^2 + (2y + 1)^2 = 1 ### Step 2: Expand and Arrange Circle Equation Expanding the expression: 2x^2 - 2x + 2y^2 + y = 4x^2 + 4y^2 + 4y + 1 2x^2 + 2y^2 + 2x + 3y + 1 = 0 Dividing full equation by 2: x^2 + y^2 + x + frac32y + frac12 = 0 ### Step 3: Extract Center and Radius textCenter (a, b) = left(-frac12, -frac34right) r^2 = g^2 + f^2 - c = left(frac12right)^2 + left(frac34right)^2 - frac12 = frac14 + frac916 - frac12 = frac516 Evaluating frac15abr^2: frac15 cdot left(-frac12right) cdot left(-frac34right)frac516 = fracfrac458frac516 = 18 ### Pattern Recognition Recognizing that operatornameRe(w) + operatornameRe(barw) = 2operatornameRe(w) avoids complex algebraic division on the second fractional expression completely. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Mathematics: Complex Numbers Class 11 Mathematics: Circles

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