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Chemical Bonding and Molecular Structure appeared 42 times across 3 years — 4.9% of Chemistry. This question is from VSEPR Theory.

Year 2026 2025 2024 Total
Questions 12 14 16 42

Given below are two statements: Statement (I) : for C F₃ , all three possible structures may be drawn as follows.
ClF3 structure variant I for Q44
The prompt displays three configurations of chlorine trifluoride with differing spatial positions for its two lone electron pairs.
ClF3 structure variant I for Q44
The prompt displays three configurations of chlorine trifluoride with differing spatial positions for its two lone electron pairs.
ClF3 structure variant I for Q44
The prompt displays three configurations of chlorine trifluoride with differing spatial positions for its two lone electron pairs.
Statement (II) : Structure III is most stable, as the orbitals having the lone pairs are axial, where the p- bp repulsion is minimum. In the light of the above statements, choose the most appropriate answer from the options given below:

ClF3 structure variant I for Q44
The prompt displays three configurations of chlorine trifluoride with differing spatial positions for its two lone electron pairs.

Solution & Explanation

Related Formula
Steric Number for ClF₃ = (7+3)/(2) = 5 sp³d hybridization (Trigonal Bipyramidal geometry)
Core Logic
  • Statement I is correct: The three structural arrangements represent the different ways to place three bond pairs and two lone pairs within a trigonal bipyramidal grid.
  • Statement II is incorrect: According to VSEPR theory and Bent's rule, in sp³d hybridization, lone pairs must occupy equatorial positions to minimize strong 90^° lone pair-bond pair (p-bp) repulsions. Placing them axially maximizes repulsions, making that structure the least stable, not the most stable.
Pattern Recognition

For sp³d configurations (Trigonal Bipyramidal), lone pairs ALWAYS prefer equatorial sites where they experience 120^circ interactions, minimizing severe 90^circ structural strains. This results in the classic stable T-shaped configuration for ClF₃.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

More Chemical Bonding and Molecular Structure Previous-Year Questions — Page 9

Q77 jee_main_2024_31_jan_morning Molecular Orbital Theory
The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals A. have the same energy B. have the minimum overlap C. have same symmetry about the molecular axis D. have different symmetry about the molecular axis Choose the most appropriate from the options given below:
  • A. A, B, C only
  • B. A and C only
  • C. B, C, D only
  • D. B and D only

Solution

Core Logic

Conditions for the linear combination of atomic orbitals (LCAO) to form molecular orbitals:

  • The combining atomic orbitals must have the same or nearly the same energy.
  • The combining atomic orbitals must have the same symmetry about the molecular axis.
  • The combining atomic orbitals must overlap to the maximum extent (not minimum).
Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q85 jee_main_2024_31_jan_morning Hybridization
The number of species from the following in which the central atom uses sp³ hybrid orbitals in its bonding is NH₃, SO₂, SiO₂, BeCl₂, CO₂, H₂O, CH₄, BF₃
Numerical Answer. Answer: 4 to 4

Solution

Core Logic

Analyzing the hybridization of the central atom in each species:

  • NH₃: 3 bp + 1 lp = 4 electron domains arrow sp³
  • SO₂: 2 bp + 1 lp = 3 electron domains arrow sp²
  • SiO₂: A giant covalent network where each Si is bonded to 4 oxygens tetrahedrally arrow sp³
  • BeCl₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • CO₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • H₂O: 2 bp + 2 lp = 4 electron domains arrow sp³
  • CH₄: 4 bp + 0 lp = 4 electron domains arrow sp³
  • BF₃: 3 bp + 0 lp = 3 electron domains arrow sp²
  • Total species with sp³ hybridization: NH₃, SiO₂, H₂O, CH₄. Total count = 4.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)