### Core Logic Let us compute the concentration of both solutions: textConcentration of Solution 1 = frac10text mol10text L = 1text mol/L $ \text{Concentration of Solution 1} = \frac{10\text{ mol}}{10\text{ L}} = 1\text{ mol/L} $ textConcentration of Solution 2 = frac1text mol1text L = 1text mol/L $ \text{Concentration of Solution 2} = \frac{1\text{ mol}}{1\text{ L}} = 1\text{ mol/L} $ Since concentration is identical, both systems share matching compositions. Consequently, all **intensive properties** (independent of mass/size) like concentration, density, and molar heat capacity remain exactly equal. ### Step 1: Identifying the Variable Gibbs free energy (G$G$) is an **extensive property** that scales directly with the amount of matter in the system. Because Solution 1 contains a larger total mass and volume than Solution 2, its overall Gibbs free energy value is different. ### Pattern Recognition Shortcut: Look for the only extensive property in the options. Density, concentration, and molar parameters are always intensive. Gibbs free energy (G$G$) scales with total matter quantity. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Chemical Thermodynamics