If equal volumes of mathrmAB_2 and XY (both are salts) aqueous solutions are mixed, which of the following combination will give a precipitate of mathrmAY_2 at 300mathrmK? (Given mathrmK_sp (at 300mathrmK) for mathrmAY_2 = 5.2 times 10^-7)

Solution & Explanation

### Related Formula Condition for precipitation step to happen dynamically: Q_mathrmsp > K_mathrmsp where Ionic Product Q_mathrmsp = [mathrmA^2+][mathrmY^-]^2. ### Core Logic When equal volumes are combined, total fluid volume doubles, meaning individual concentrations are exactly cut in half: [mathrmA^2+] = frac[mathrmAB_2]_02, quad [mathrmY^-] = frac[mathrmXY]_02 Let's calculate Q_mathrmsp value for item layout (3): * [mathrmA^2+] = frac2.0 times 10^-22 = 10^-2\ mathrmM * [mathrmY^-] = frac2.0 times 10^-22 = 10^-2\ mathrmM * Evaluating total value: Q_mathrmsp = (10^-2) times (10^-2)^2 = 10^-6 * Comparing arrays: 10^-6 > 5.2 times 10^-7, confirming precipitation conditions are satisfied. ### Pattern Recognition Do not skip the dilution factor! Halving initial chemical molar values before calculating the reaction quotients prevents incorrect combinations. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Equilibrium

Reference Study Guides

Equilibrium

More Equilibrium Previous-Year Questions — Page 6

Q62 jee_main_2024_31_jan_morning Equilibrium Constant
For the given reaction, choose the correct expression of K_C from the following :- Fe_(aq)^3+ + SCN_(aq)^- rightleftharpoons (FeSCN)_(aq)^2+
  • A. K_C = frac[FeSCN^2+][Fe^3+][SCN^-]
  • B. K_C = frac[Fe^3+][SCN^-][FeSCN^2+]
  • C. K_C = frac[FeSCN^2+][Fe^3+]^2[SCN^-]^2
  • D. K_C = frac[FeSCN^2+]^2[Fe^3+][SCN^-]

Solution

### Related Formula K_C = frac[textProducts][textReactants] ### Core Logic K_C = fractextProducts ion conc.textReactants ion conc. K_C = frac[FeSCN^2+][Fe^3+][SCN^-] ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Equilibrium

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