0.1mathrm~mol$0.1\mathrm{~mol}$ of the following given antiviral compound (P) will weigh times 10^-1mathrm~g$\times 10^{-1}\mathrm{~g}$

(Given : molar mass in mathrmg cdot mol^-1$\mathrm{g \cdot mol}^{-1}$ H: 1, C: 12, N: 14, O: 16, F: 19, I: 127)

### Core Logic Adenine (A) base pairs with Thymine (T) with 2 hydrogen bonds, and Cytosine (C) base pairs with Guanine (G) with 3 hydrogen bonds. For the given DNA strand: A rightarrow T$A \rightarrow T$ T rightarrow A$T \rightarrow A$ G rightarrow C$G \rightarrow C$ C rightarrow G$C \rightarrow G$ T rightarrow A$T \rightarrow A$ T rightarrow A$T \rightarrow A$ C rightarrow G$C \rightarrow G$ A rightarrow T$A \rightarrow T$ ### Step 1: Sequence Matching Given sequence: A T G C T T C A Complementary: T A C G A A G T

### Pattern Recognition DNA base pairing strictly follows Chargaff's rule: A=T and G≡C. Just swap A with T, and C with G in the exact order. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules

### Related Formula Factual knowledge of biopolymers and their fundamental repeating units (monomers). ### Core Logic Analyzing each polymer component: * **Starch** is a polymer composed entirely of alpha$\alpha$-glucose units. * **Cellulose** is a linear structural polymer consisting of linear chains of beta$\beta$-glucose units. * **Nucleic acids** (DNA/RNA) are long chains composed of repeating nucleotide units. * **Proteins** are polypeptides made from combined alpha$\alpha$-amino acid sequences. ### Step 1: Final Match Alignment Matching structural links properly leads cleanly to the configuration: A-II, B-III, C-I, D-IV. ### Pattern Recognition Standard memorization trick: Plants store starch using alpha linkers, but build rigid cell walls via beta linkers. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules

### Related Formula Nucleotides bond phosphodiester linkage: textNucleotide_1 - textO - textP(=textO)(textO^-) - textO - textNucleotide_2$$\text{Nucleotide}_1 - \text{O} - \text{P}(=\text{O})(\text{O}^-) - \text{O} - \text{Nucleotide}_2$$ ### Core Logic Two nucleotides are joined together by phosphodiester linkage between 5'$5'$ and 3'$3'$ carbon atoms of the pentose sugar.

### Pattern Recognition Proteins rightarrow$\rightarrow$ Peptide, Carbohydrates rightarrow$\rightarrow$ Glycosidic, Proteins/Cysteine rightarrow$\rightarrow$ Disulphide, Nucleic Acids rightarrow$\rightarrow$ Phosphodiester linkage. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules

### Core Logic Proteins are natural biopolymers. The fundamental building blocks (monomers) of all naturally occurring proteins are alpha$\alpha$-amino acids. In these molecules, both the amino group (-NH_2$-NH_2$) and the carboxyl group (-COOH$-COOH$) are attached to the exact same carbon atom, designated as the alpha$\alpha$-carbon. Because they are polymers of alpha$\alpha$-amino acids linked by peptide bonds, the hydrolysis of proteins (acidic, basic, or enzymatic) will cleave these peptide bonds to yield the constituent alpha$\alpha$-amino acids. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules

### Core Logic A. RNA is regarded as the reserve of genetic information. (False - DNA is the reserve of genetic information). B. DNA molecule self-duplicates during cell division. (True - through replication). C. DNA synthesizes proteins in the cell. (False - RNA molecules synthesize proteins via translation, DNA only provides the code). D. The message for the synthesis of particular proteins is present in DNA. (True - the genetic code lies in the base sequence of DNA). E. Identical DNA strands are transferred to daughter cells. (True - through accurate replication and cell division, genetic continuity is maintained). ### Step 1: Final Conclusion The true statements are B, D, and E. Total number of correct statements is 3. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules