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The compound that is white in color is

Solution & Explanation

### Core Logic Analyzing the colors of the given salts: Lead sulphate (PbSO_4) is white. Ammonium sulphide ((NH_4)_2S) is soluble/colorless in solution. Lead iodide (PbI_2) is bright yellow. Ammonium arsinomolybdate is yellow. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Salt Analysis

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Salt Analysis

More Salt Analysis Previous-Year Questions — Page 2

Q81 jee_main_2024_31_jan_morning Anion Identification
Molar mass of the salt from NaBr, NaNO_3, KI and CaF_2 which does not evolve coloured vapours on heating with concentrated H_2SO_4 is ________ textg mol^-1. (Molar mass in textg mol^-1: Na: 23, N: 14, K: 39, O: 16, Br: 80, I: 127, F: 19, Ca: 40)
Numerical Answer. Answer: 78 to 78

Solution

### Step 1: Analyzing the reactions with Concentrated H2SO4 NaBr xrightarrowtextconc. H_2SO_4 Br_2 (Reddish-brown vapour evolves) NaNO_3 xrightarrowtextconc. H_2SO_4 NO_2 (Brown vapour evolves) KI xrightarrowtextconc. H_2SO_4 I_2 (Violet vapour evolves) CaF_2 xrightarrowtextconc. H_2SO_4 HF (Colorless vapour evolves) Thus, CaF_2 does not evolve colored vapours. ### Step 2: Calculating Molar Mass Molar mass of CaF_2: Ca = 40 F_2 = 2 times 19 = 38 textMolar mass = 40 + 38 = 78 text g/mol ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Salt Analysis

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