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Chemical Bonding and Molecular Structure appeared 42 times across 3 years — 4.9% of Chemistry. This question is from Dipole Moment.

Year 2026 2025 2024 Total
Questions 12 14 16 42

Given below are two statements: Statement-I: Since fluorine is more electronegative than nitrogen, the net dipole moment of NF₃ is greater than NH₃. Statement-II: In NH₃, the orbital dipole due to lone pair and the dipole moment of NH bonds are in opposite direction, but in NF₃ the orbital dipole due to lone pair and dipole moments of N-F bonds are in same direction. In the light of the above statements. Choose the most appropriate from the options given below.

Solution & Explanation

Core Logic

Statement I: The net dipole moment of NH₃ (1.47 D) is actually greater than that of NF₃ (0.23 D). Therefore, Statement I is false.

Statement II: In NH₃, the N-H bond dipole moments (pointing towards the more electronegative N) reinforce the orbital dipole moment of the lone pair. In NF₃, the N-F bond dipole moments point away from N (towards the more electronegative F), opposing the orbital dipole moment of the lone pair. This partial cancellation in NF₃ makes its net dipole moment lower. Therefore, Statement II is also false, as it reverses the correct orientations.

Dipole moments in NH3 and NF3 diagram for Q75 - JEE Main 2024 Evening
Dipole moments in NH3 and NF3 diagram for Q75 - JEE Main 2024 Evening
Dipole moments in NH3 and NF3 diagram for Q75 - JEE Main 2024 Evening
Dipole moments in NH3 and NF3 diagram for Q75 - JEE Main 2024 Evening

Step 1: Final Conclusion

Since both statements assert the opposite of established facts regarding NH₃ and NF₃, both are false.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

More Chemical Bonding and Molecular Structure Previous-Year Questions — Page 9

Q77 jee_main_2024_31_jan_morning Molecular Orbital Theory
The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals A. have the same energy B. have the minimum overlap C. have same symmetry about the molecular axis D. have different symmetry about the molecular axis Choose the most appropriate from the options given below:
  • A. A, B, C only
  • B. A and C only
  • C. B, C, D only
  • D. B and D only

Solution

Core Logic

Conditions for the linear combination of atomic orbitals (LCAO) to form molecular orbitals:

  • The combining atomic orbitals must have the same or nearly the same energy.
  • The combining atomic orbitals must have the same symmetry about the molecular axis.
  • The combining atomic orbitals must overlap to the maximum extent (not minimum).
Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q85 jee_main_2024_31_jan_morning Hybridization
The number of species from the following in which the central atom uses sp³ hybrid orbitals in its bonding is NH₃, SO₂, SiO₂, BeCl₂, CO₂, H₂O, CH₄, BF₃
Numerical Answer. Answer: 4 to 4

Solution

Core Logic

Analyzing the hybridization of the central atom in each species:

  • NH₃: 3 bp + 1 lp = 4 electron domains arrow sp³
  • SO₂: 2 bp + 1 lp = 3 electron domains arrow sp²
  • SiO₂: A giant covalent network where each Si is bonded to 4 oxygens tetrahedrally arrow sp³
  • BeCl₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • CO₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • H₂O: 2 bp + 2 lp = 4 electron domains arrow sp³
  • CH₄: 4 bp + 0 lp = 4 electron domains arrow sp³
  • BF₃: 3 bp + 0 lp = 3 electron domains arrow sp²
  • Total species with sp³ hybridization: NH₃, SiO₂, H₂O, CH₄. Total count = 4.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

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