Two sources of light emit with a power of 200 W$200\text{ W}$. The ratio of number of photons of visible light emitted by each source having wavelengths 300 nm$300\text{ nm}$ and 500 nm$500\text{ nm}$ respectively, will be:

Related Formula

Core Logic

Using Einstein's Photoelectric equation for the two cases:

Case 1 (Wavelength λ$\lambda$, Stopping Potential 8 V$8\mathrm{\,V}$):

Case 2 (Wavelength 3λ$3\lambda$, Stopping Potential 2 V$2\mathrm{\,V}$):

Step 2: Solving the Equations

Multiply equation (ii) by 4 to eliminate e$e$:

Equating this to equation (i):

Divide entirely by hc$hc$:

Chapter Mix

Class 12 Physics: Dual Nature Of Radiation And Matter