The product A formed in the following reaction is:
Diazotization and Sandmeyer Reaction diagram for Q71 - JEE Main 2024 Evening
The diagram details aniline undergoing diazotization with sodium nitrite and hydrochloric acid, followed by treatment with cuprous chloride.

Solution & Explanation

### Related Formula textAr-NH_2 xrightarrowtextNaNO_2 + textHCl, 0^circtextC textAr-N_2^+textCl^- xrightarrowtextCu_2textCl_2 textAr-Cl ### Core Logic The schematic outlines a classic sequence: 1. **Diazotization Step**: Aniline reacts with nitrous acid generated in situ (textNaNO_2 + textHCl) at low temperature (0-5^circtextC) to form benzene diazonium chloride intermediate. 2. **Sandmeyer Replacement Step**: Treating the diazonium salt with cuprous chloride (textCu_2textCl_2) results in replacement of the diazo group by a chlorine atom. ### Step 1: Visual Verification Tracing structural shifts through intermediates validates the final outcome:
Diazotization and Sandmeyer Reaction solution diagram for Q71 - JEE Main 2024 Evening
The diagram details aniline undergoing diazotization with sodium nitrite and hydrochloric acid, followed by treatment with cuprous chloride.
### Pattern Recognition Aniline rightarrow Diazonium salt rightarrow Chlorobenzene via standard Sandmeyer synthesis protocols. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Organic Compounds Containing Nitrogen

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