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Match List I with List II:
List IList II
A. oint vecB cdot dvecl = mu_0 i_c + mu_0 varepsilon_0 fracdphi_EdtI. Gauss' law for electricity
B. oint vecE cdot dvecl = -fracdphi_BdtII. Gauss' law for magnetism
C. oint vecE cdot dvecA = fracQvarepsilon_0III. Faraday law
D. oint vecB cdot dvecA = 0IV. Ampere - Maxwell law
Choose the correct answer from the options given below:

Solution & Explanation

### Core Logic Let's review the fundamental Maxwell's equations: 1. **Ampere - Maxwell Law** relates the magnetic path integral to conduction current and displacement current: oint vecB cdot dvecl = mu_0 i_c + mu_0 varepsilon_0 fracdphi_Edt implies textA - IV 2. **Faraday's Law of Induction** states that changing magnetic flux induces an electromotive force (EMF): oint vecE cdot dvecl = -fracdphi_Bdt implies textB - III 3. **Gauss's Law for Electricity** relates net electric flux to enclosed charge: oint vecE cdot dvecA = fracQvarepsilon_0 implies textC - I 4. **Gauss's Law for Magnetism** states that magnetic monopoles do not exist: oint vecB cdot dvecA = 0 implies textD - II ### Step 1: Match Evaluation The match configurations are: * A rightarrow IV * B rightarrow III * C rightarrow I * D rightarrow II This perfectly corresponds to Option (3). ### Pattern Recognition Understand the integral geometries: Path integrals (line integrals oint cdot dvecl) correspond to circulating fields (induction laws like Ampere/Faraday). Surface integrals (flux integrals oint cdot dvecA) correspond to bounded charge states (Gauss laws). ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Electromagnetic Waves Class 12 Physics: Electrostatics Class 12 Physics: Magnetism and Matter

Reference Study Guides

More Electromagnetic Waves Previous-Year Questions — Page 5

Q40 jee_main_2024_31_jan_morning Energy Density Of EM Waves
In a plane EM wave, the electric field oscillates sinusoidally at a frequency of 5 times 10^10 mathrm~Hz and an amplitude of 50 mathrm~Vm^-1. The total average energy density of the electromagnetic field of the wave is : [Use varepsilon_0 = 8.85 times 10^-12 \, textC^2 / textNm^2 ]
  • A. 1.106 times 10^-8 \, mathrmJm^-3
  • B. 4.425 times 10^-8 mathrm~Jm^-3
  • C. 2.212 times 10^-8 mathrm~Jm^-3
  • D. 2.212 times 10^-10 mathrm~Jm^-3

Solution

### Related Formula U_texttotal average = frac12epsilon_0 E_0^2 ### Core Logic For an electromagnetic wave, the total average energy density is the sum of the average energy density of the electric field and the magnetic field. They are equal, so: U_textavg = U_E + U_B = 2U_E = 2 left( frac14epsilon_0 E_0^2 right) = frac12epsilon_0 E_0^2 Where E_0 is the amplitude of the electric field. ### Step 2: Substitution Given: E_0 = 50 mathrm\, V/m epsilon_0 = 8.85 times 10^-12 mathrm\, C^2/(Ncdot m^2) U_textavg = frac12 times (8.85 times 10^-12) times (50)^2 U_textavg = frac12 times 8.85 times 10^-12 times 2500 U_textavg = 1.10625 times 10^-8 mathrm\, J/m^3 ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Electromagnetic Waves

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