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Equilibrium appeared 36 times across 3 years — 4.2% of Chemistry. This question is from Kp and Kc Relationship.

Year 2026 2025 2024 Total
Questions 10 18 8 36

For the reaction N₂O₄(g) leftharpoons 2NO₂(g) Kₚ = 0.492 atm at 300K . Kc for the reaction at same temperature is ______ × 10⁻² . (Given: R = 0.082 L atm mol⁻¹ K⁻¹)

Numerical Answer Type:
Enter a numerical value Answer: 2 to 2 +4 marks

Solution & Explanation

Related Formula
Kₚ = Kc · (RT)Δ ng
Core Logic

For the given gaseous equilibrium reaction:

N₂O₄(g) leftharpoons 2NO₂(g)

First, find the change in the number of moles of gas (Δ ng):

Δ ng = nₚ - nᵣ = 2 - 1 = 1
Step 1: Calculation

Substitute the given values into the Kₚ - Kc relationship: Kₚ = 0.492 R = 0.082 T = 300 K

0.492 = Kc · (0.082 × 300)¹ Kc = (0.492)/(0.082 × 300) Kc = (0.492)/(24.6)

Kc = 0.02

Converting to the requested format (x × 10⁻²):

Kc = 2 × 10⁻²

So, the value is 2.

Chapter Mix

Class 11 Chemistry: Equilibrium

Reference Study Guides

More Equilibrium Previous-Year Questions — Page 8

Q62 jee_main_2024_31_jan_morning Equilibrium Constant
For the given reaction, choose the correct expression of KC from the following :- Fe(aq)³⁺ + SCN(aq)⁻ leftharpoons (FeSCN)(aq)²⁺
  • A. KC = [FeSCN²⁺][Fe³⁺][SCN⁻]
  • B. KC = [Fe³⁺][SCN⁻][FeSCN²⁺]
  • C. KC = [FeSCN²⁺][Fe³⁺]²[SCN⁻]²
  • D. KC = [FeSCN²⁺]²[Fe³⁺][SCN⁻]

Solution

Related Formula
KC = [Products][Reactants]
Core Logic
KC = Products ion conc.Reactants ion conc. KC = [FeSCN²⁺][Fe³⁺][SCN⁻]
Chapter Mix

Class 11 Chemistry: Equilibrium

More Equilibrium Questions — jee_main_2024_29_jan_morning

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