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If the average depth of an ocean is 4000text m and the bulk modulus of water is 2 times 10^9text Ncdottextm^-2, then the fractional compression fracDelta VV of water at the bottom of the ocean is alpha times 10^-2. The value of alpha is ______. (Given, g = 10text mcdottexts^-2, rho = 1000text kgcdottextm^-3).

Numerical Answer Type:
Enter a numerical value Answer: 2 to 2 +4 marks

Solution & Explanation

### Related Formula B = -fracDelta Pleft(fracDelta VVright) implies left|fracDelta VVright| = fracDelta PB Where the hydrostatic pressure difference at depth is Delta P = rho g h. ### Core Logic Calculate the gauge pressure Delta P at the ocean floor (h = 4000text m): Delta P = 1000 times 10 times 4000 = 4 times 10^7text N/m^2 ### Step 1: Compute fractional volume change left|fracDelta VVright| = frac4 times 10^72 times 10^9 = 2 times 10^-2 ### Step 2: Match parameters to find alpha Comparing 2 times 10^-2 to alpha times 10^-2 gives: alpha = 2 ### Pattern Recognition Hydrostatic scaling expressions yield precise decade cancellations when tracked directly relative to high exponent elastic constants like Bulk Moduli. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Mechanical Properties of Solids / Fluids

Reference Study Guides

More Mechanical Properties of Solids Previous-Year Questions — Page 4

Q58 jee_main_2024_31_jan_morning Bulk Modulus
The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02\% is ________ mathrmm. (Take density of sea water = 10^3mathrm\ kgm^-3, Bulk modulus of rubber = 9 times 10^8mathrm\ Nm^-2, and g = 10mathrm\ ms^-2)
Numerical Answer. Answer: 18 to 18

Solution

### Related Formula beta = frac-Delta PfracDelta VV Delta P = rho g h ### Core Logic The change in pressure Delta P is the hydrostatic pressure at depth h. Delta P = -beta fracDelta VV rho g h = -beta fracDelta VV ### Step 2: Calculation Given values: rho = 10^3mathrm\,kg/m^3 g = 10mathrm\,m/s^2 beta = 9 times 10^8mathrm\,N/m^2 fracDelta VV = -0.02\% = -frac0.02100 Substitute into the equation: 10^3 times 10 times h = - (9 times 10^8) times left(-frac0.02100right) 10^4 times h = 9 times 10^8 times 2 times 10^-4 10^4 h = 18 times 10^4 h = 18mathrm\,m ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Mechanical Properties Of Solids Class 11 Physics: Mechanical Properties Of Fluids

More Mechanical Properties of Solids Questions — jee_main_2024_27_jan_morning

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