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If the system of equations 2x - y + z = 4 5x + lambda y + 3z = 12 100x - 47y + mu z = 212 has infinitely many solutions, then mu - 2lambda is equal to :

Solution & Explanation

### Related Formula According to Cramer's Rule, for a system of linear equations to have infinitely many solutions, the main determinant Delta and all directional determinants Delta_1, Delta_2, Delta_3 must equal zero simultaneously. ### Core Logic Set up the directional determinant equation Delta_3 = 0 by replacing the third column with the constant vector: Delta_3 = left| beginmatrix 2 & -1 & 4 \\ 5 & lambda & 12 \\ 100 & -47 & 212 endmatrix right| = 0 Expand the determinant along the first row: 2[212lambda - 12(-47)] - (-1)[5(212) - 12(100)] + 4[5(-47) - 100lambda] = 0 2[212lambda + 564] + 1[1060 - 1200] + 4[-235 - 100lambda] = 0 424lambda + 1128 - 140 - 940 - 400lambda = 0 24lambda + 48 = 0 implies lambda = -2 ### Step 1: Solve for Mu using the main determinant Set the primary coefficient matrix determinant Delta = 0 and substitute lambda = -2: Delta = left| beginmatrix 2 & -1 & 1 \\ 5 & -2 & 3 \\ 100 & -47 & mu endmatrix right| = 0 Expand the determinant along the first row: 2[-2mu - 3(-47)] - (-1)[5mu - 3(100)] + 1[5(-47) - (-2)(100)] = 0 2[-2mu + 141] + [5mu - 300] + [-235 + 200] = 0 -4mu + 282 + 5mu - 300 - 35 = 0 mu - 53 = 0 implies mu = 53 ### Step 2: Calculate the Target Value Substitute the values of mu and lambda into the expression: mu - 2lambda = 53 - 2(-2) = 53 + 4 = 57 ### Pattern Recognition When solving systems of equations for infinite solution parameters, choosing a directional determinant that excludes one of the variables simplifies the problem into two separate single-variable equations. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Mathematics: Matrices and Determinants

Reference Study Guides

More Matrices and Determinants Previous-Year Questions — Page 6

Q70 2025 Cofactors and Determinant Value
Let mathrmA = left[mathbfa_mathrmijright] = beginbmatrix log_5128 & log_45 \\ log_58 & log_425 endbmatrix . If A_ij is the cofactor of a_ij , C_ij = sum_k=1^2 a_ik A_jk , 1 leq i, j leq 2 , and C = [C_ij] , then 8|C| is equal to:
  • A. 262
  • B. 288
  • C. 242
  • D. 222

Solution

### Related Formula sum_k a_ik A_jk = delta_ij |A| implies C = beginbmatrix |A| & 0 \\ 0 & |A| endbmatrix implies |C| = |A|^2 ### Core Logic Evaluate the determinant of matrix A: |A| = (log_5 128)(log_4 25) - (log_4 5)(log_5 8) Using change of base rules: |A| = left(7log_5 2right)left(2log_4 5right) - left(frac12log_2 5right)left(3log_5 2right) |A| = 14left(log_5 2 cdot frac12log_2 5right) - frac32 = 7 - 1.5 = 5.5 = frac112 ### Step 1: Compute |C| and evaluate response target Since matrix properties dictate |C| = |A|^2: |C| = left(frac112right)^2 = frac1214 Evaluate targeted multiplier: 8|C| = 8 times frac1214 = 2 times 121 = 242 ### Pattern Recognition Recognize the core cofactor theorem identity instantly: multiplying rows by cofactors of other rows creates zero elements, yielding basic diagonal scalar structures matching matrix attributes. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Mathematics: Matrices and Determinants

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