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If intfrac2x^2+5x+9sqrtx^2+x+1dx=xsqrtx^2+x+1+alphasqrtx^2+x+1+betalog_eleft|x+frac12+sqrtx^2+x+1right|+C where C is the constant of integration, then alpha+2beta is equal to \_\_\_\_. [cite: 3419, 3420]

Numerical Answer Type:
Enter a numerical value Answer: 16 +4 marks

Solution & Explanation

### Related Formula Standard integration templates for quadratic forms: int sqrtt^2 + k^2 dt = fract2sqrtt^2+k^2 + frack^22lnleft|t + sqrtt^2+k^2right| int frac1sqrtt^2 + k^2 dt = lnleft|t + sqrtt^2+k^2right| ### Core Logic Decompose the numerator using polynomial differentiation components : 2x^2 + 5x + 9 = A(x^2 + x + 1) + B(2x + 1) + C Equating coefficients dynamically yields : - For x^2: A = 2 . - For x: A + 2B = 5 Rightarrow 2 + 2B = 5 Rightarrow B = frac32 . - Constant: A + B + C = 9 Rightarrow 2 + frac32 + C = 9 Rightarrow C = frac112 . Rewrite the integrand into three parts : 2int sqrtx^2+x+1 dx + frac32int frac2x+1sqrtx^2+x+1 dx + frac112int frac1sqrtx^2+x+1 dx ### Step 1: Complete Quadratics & Integrate Format using completing the square technique: x^2 + x + 1 = left(x + frac12right)^2 + left(fracsqrt32right)^2. 1. First Integral evaluation: 2 left[ fracleft(x+frac12right)2sqrtx^2+x+1 + frac38lnleft|x+frac12+sqrtx^2+x+1right| right] = left(x+frac12right)sqrtx^2+x+1 + frac34lnleft|x+frac12+sqrtx^2+x+1right| 2. Second Integral evaluation : frac32 cdot 2sqrtx^2+x+1 = 3sqrtx^2+x+1 3. Third Integral evaluation : frac112lnleft|x+frac12+sqrtx^2+x+1right| ### Step 2: Collect Like Terms Gather and combine matching factor parameters: textTotal = left(x + frac12 + 3right)sqrtx^2+x+1 + left(frac34 + frac112right)lnleft|x+frac12+sqrtx^2+x+1right| textTotal = left(x + frac72right)sqrtx^2+x+1 + frac254lnleft|x+frac12+sqrtx^2+x+1right| = xsqrtx^2+x+1 + frac72sqrtx^2+x+1 + frac254lnleft|x+frac12+sqrtx^2+x+1right| ### Step 3: Extract Coefficients Compare directly against the given expression variables : alpha = frac72, quad beta = frac254 alpha + 2beta = frac72 + 2left(frac254right) = frac72 + frac252 = frac322 = 16 ### Pattern Recognition When dividing large numerators containing x^2 elements over quadratic square roots, using matching coefficient expansion rules prevents lengthy substitution errors completely. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Mathematics: Integrals

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